WebDec 6, 2015 · Best Answer sin2x - cosx = 0 2sinx cos x - cosx = 0 factor out cosx cosx [ 2sinx - 1] = 0 set each factor to 0 cosx = 0 and this happens at 180° 2sinx - 1 = 0 add 1 to both sides 2sinx = 1 divide by 2 sinx = 1/2 and … WebTrigonometry Solve for x sin (2x)sin (x)=cos (x) sin(2x) sin(x) = cos (x) sin ( 2 x) sin ( x) = cos ( x) Subtract cos(x) cos ( x) from both sides of the equation. sin(2x)sin(x)−cos(x) = 0 sin ( …
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WebFree math problem solver answers your trigonometry homework questions with step-by-step explanations. WebTrigonometry Solve for x sin (2x)sin (x)=cos (x) sin(2x) sin(x) = cos (x) sin ( 2 x) sin ( x) = cos ( x) Subtract cos(x) cos ( x) from both sides of the equation. sin(2x)sin(x)−cos(x) = 0 sin ( 2 x) sin ( x) - cos ( x) = 0 Simplify each term. Tap for more steps... 2sin2(x)cos(x)−cos(x) = 0 2 sin 2 ( x) cos ( x) - cos ( x) = 0 how did they make their money
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WebSep 18, 2015 · Solve sin x = cos 2x Explanation: Apply trig identity: cos2x = 1 −2sin2x sinx = 1 −2sin2x. Solve the quadratic equation: 2sin2x + sinx − 1 = 0 Since (a - b + c = 0), use Shortcut. Two real roots: sin x = -1 and sinx = − c a = 1 2. sinx = 1 2 --> x = 30 deg and x = 150 deg ( π 6 and 5π 6) sin x = -1 --> x = 270 deg ( 3π 2) General solutions: WebHint: sin(2x) = 2sinxcosx so your equation becomes : 2sinxcosx+cosx = 0 cosx(2sinx +1) = 0. If 41 is a solution of sin2x = pcosx , then p is? (a) -3 (b) 0 (c) 1 (d) -1 I think option (b) is correct, but I want solution. p = 0.4948 Explanation: sin2x = pcosx ⇔ 2sinxcosx = pcosx or cosx(2sinx− p) = 0 ... Web= \dfrac {\sin (x)} {1 + \cos (x)} = 1+cos(x)sin(x) The above identities can be re-stated by squaring each side and doubling all of the angle measures. The results are as follows: \sin^2 (x) = \frac {1} {2} \big [1 - \cos (2x)\big] sin2(x)= 21[1 −cos(2x)] \cos^2 (x) = \frac {1} {2} \big [1 + \cos (2x)\big] cos2(x)= 21[1 +cos(2x)] how did they make thor fat